In this question, the table is made from an equation that follows y=ax+b. To find the equation, it would be easier to use x=0 so you can exclude the a value and find the value of b. From the description, you can find that x=0 will result in y=2. Then if you put it into the equation:
y=ax+b 2=a(0)+b b=2
Now we need to find the value of a. You can do this by inserting any value of x and y beside x=0. Let's try to use x=-2 and y=-6 y=ax+b -6 =a(-2)+2 -6= -2a+2 -2a= -6-2 -2a=-8 a= -8/-2=4
