Respuesta :
6(x^2-1)(6x-1/6(x+1))
On factoring (x^2-1)=(x+1)(x-1)
= 6(x-1)(x+1)(6x-1/6(x+1))
Cancelling (x+1) from numerator and denominator we get,
= 6(x-1)(6x-1)/6
Cancelling 6 we get,
= (x-1)(6x-1)
On factoring (x^2-1)=(x+1)(x-1)
= 6(x-1)(x+1)(6x-1/6(x+1))
Cancelling (x+1) from numerator and denominator we get,
= 6(x-1)(6x-1)/6
Cancelling 6 we get,
= (x-1)(6x-1)