Suppose that maria has 150 coins consisting of pennies, nickels, and dimes. the number of nickels she has is 14 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. how many coins of each kind does she have?
Let p, n, d represent the number of pennies, nickels, and dimes respectively. The problem statement tells us .. p +n +d = 150 .. 2p -n = 14 .. 3p -d = 22 Add these three equations to find the number of pennies. .. (p +n +d) +(2p -n) +(3p -d) = 150 +14 +22 .. 6p = 186 .. p = 31 .. n = 2*31 -14 = 48 .. d = 3*31 -22 = 71
