Respuesta :

41+42+43. Those three numbers add up to 126
Dilnoza
let smallest be x
so next must be 1 bigger...x+1
and third must be 1 bigger still... x+2

so, x+ x+1 + x+2 = 126
3x+3 = 126
3x = 123
x = 123/3
x = 41

So, three numbers are 41, 42 and 43.

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