Answer:
Square
Step-by-step explanation:
It is given that the coordinates of polygon graphed in the first quadrant with one vertex on the origin are (0,0), (a,0), (a,a), (0,a).
Let A=(0,0),
B=9(a,0),
C=(a,a) and
D=(0,a)
Then, using the distance formula, we have
[tex]AB=\sqrt{(a-0)^2+(0-0)^2}=a[/tex],
[tex]BC=\sqrt{(a-a)^2+(a-0)^2}=a[/tex],
[tex]CD=\sqrt{(a-a)^2+(a-0)^2}=a[/tex]and
[tex]DA=\sqrt{(0-0)^2+(a-0)^2}=a[/tex]
Since, all the sides of the given polygon are equal, therefore it is a square.
